12w^2-13w+3=0

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Solution for 12w^2-13w+3=0 equation: 



12w^2-13w+3=0

a = 12; b = -13; c = +3;
Δ = b2-4ac
Δ = -132-4·12·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*12}=\frac{8}{24}
=1/3
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*12}=\frac{18}{24}
=3/4
$

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